United States presidential election in Missouri, 1996
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This article describes the United States presidential election, 1996, in Missouri.
Since 1904, Missouri has voted for the eventual winner of the election in a presidential election, with the single exception of the 1956 election.
| Presidential Candidate | Running Mate | Party | Electoral Vote (EV) | Popular Vote (PV) | |
|---|---|---|---|---|---|
| Bill Clinton of Arkansas | Al Gore of Tennessee | Democratic | 11[1] | 1,025,935 | 47.54% |
| Bob Dole of Kansas | Jack Kemp | Republican | 0 | 890,016 | 41.24% |
| H. Ross Perot | James Campbell | Reform Party | 0 | 217,188 | 10.06% |
| Howard Phillips | Herbert Titus | U.S. Taxpayer Party | 0 | 11,521 | 0.53% |
| Harry Browne | Jo Jorgensen | Libertarian Party | 0 | 10,522 | 0.49% |
| John Hagelin | V. Tompkins | Natural Law Party | 0 | 2,287 | 0.11% |
| Ralph Nader | Winona LaDuke | Write-in | 0 | 534 | 0.02% |
| Charles Collins | Rosemary Giumarra | Write-in | 0 | 62 | 0.00% |
Statewide winner in bold. See main article : U.S. presidential election, 1996.
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