United States presidential election in Missouri, 1992
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This article describes the United States presidential election, 1992, in Missouri.
Since 1904, Missouri has voted for the eventual winner of the election in a presidential election, with the single exception of the 1956 election.
| Presidential Candidate | Running Mate | Party | Electoral Vote (EV) | Popular Vote (PV) | |
|---|---|---|---|---|---|
| Bill Clinton of Arkansas | Al Gore of Tennessee | Democratic | 11[1] | 1,053,873 | 44.07% |
| George H. W. Bush | Dan Quayle | Republican | 0 | 811,159 | 33.92% |
| Ross Perot | James Stockdale | Independent Party | 0 | 518,741 | 21.69% |
| Andre Marrou | Nancy Lord | Libertarian Party | 0 | 7,497 | 0.31% |
Statewide winner in bold. See main article : U.S. presidential election, 1992.
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