Wasatch County, Utah
From Wikipedia, the free encyclopedia
| Wasatch County, Utah | |
| Map | |
Location in the state of Utah |
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Utah's location in the U.S. |
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| Statistics | |
| Founded | 1862 |
|---|---|
| Seat | Heber |
| Largest city | Heber |
| Area - Total - Land - Water |
1,209 sq mi (3,132 km²) 1,177 sq mi (3,049 km²) 32 sq mi (82 km²), 2.63% |
| Population - (2000) - Density |
15,215 |
| Named for: Native American word for mountain pass | |
Wasatch County is a county located in the U.S. state of Utah. As of 2000 the population was 15,215, and by 2005 was estimated at 18,974. It was named for a Ute Indian word meaning mountain pass or low place in the high mountains. Its county seat and largest city is Heber City.[1]The county is governed by a county council with an appointed county manager.[1]
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[edit] Geography
According to the U.S. Census Bureau, the county has a total area of 1,209 square miles (3,132 km²), of which, 1,177 square miles (3,049 km²) of it is land and 32 square miles (82 km²) of it (2.63%) is water.
[edit] Adjacent Counties
- Salt Lake County, Utah - (northwest)
- Summit County, Utah - (north)
- Utah County, Utah - (west)
- Duchesne County, Utah - (east)
[edit] Demographics
As of the census[2] of 2000, there were 15,215 people, 4,743 households, and 3,870 families residing in the county. The population density was 13 people per square mile (5/km²). There were 6,564 housing units at an average density of 6 per square mile (2/km²). The racial makeup of the county was 95.62% White, 0.22% Black or African American, 0.43% Native American, 0.30% Asian, 0.10% Pacific Islander, 1.96% from other races, and 1.38% from two or more races. 5.09% of the population were Hispanic or Latino of any race.
By 2005 90.0% of the county population was non-Hispanic whites. African-Americans were 0.5% of the population, a higher percentage than in neighboring Utah County. This also represented a more than 100% growth in the African American population of the county. Native Americans were now 0.8% of the population, also approaching a percentage growth of nearly 100%. Asians made up 0.6% of the population, also a large percentage growth. Latinos were 7.7% of the population, not as large a percentage growth but still a growth of over 200 people, large by Wasatch county standards.[3]
There were 4,743 households out of which 46.20% had children under the age of 18 living with them, 71.00% were married couples living together, 7.50% had a female householder with no husband present, and 18.40% were non-families. 14.30% of all households were made up of individuals and 5.00% had someone living alone who was 65 years of age or older. The average household size was 3.18 and the average family size was 3.55.
In the county, the population was spread out with 34.20% under the age of 18, 9.90% from 18 to 24, 29.00% from 25 to 44, 18.50% from 45 to 64, and 8.40% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 103.30 males. For every 100 females age 18 and over, there were 99.50 males.
The median income for a household in the county was $49,612, and the median income for a family was $52,102. Males had a median income of $37,399 versus $23,571 for females. The per capita income for the county was $19,869. About 4.20% of families and 5.20% of the population were below the poverty line, including 5.60% of those under age 18 and 4.00% of those age 65 or over.
By 2006 Wasatch County's population had risen 33.1% to 20,255.
[edit] Cities and towns
[edit] References
- ^ Find a County. National Association of Counties. Retrieved on 2008-01-31.
- ^ American FactFinder. United States Census Bureau. Retrieved on 2008-01-31.
- ^ Wasatch County QuickFacts from the US Census Bureau
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[edit] External links
Wasatch County Website: [2]

