User:ValHallASW
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- personal notebook*

\Delta b = b_\textrm{close} - b_\infty = 2,85\cdot\rho-2,3\cdot\rho = 0,55\cdot\rho
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[edit] quarin dit:

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\Delta b = b_\textrm{close} - b_\infty = 2,85\cdot\rho-2,3\cdot\rho = 0,55\cdot\rho
==


