Talk:United States presidential election, 1796
From Wikipedia, the free encyclopedia
Please see Wikipedia:Style for U.S. presidential election, yyyy for standards for all "U.S. presidential election, yyyy" pages.
Contents |
[edit] North Carolina electoral college
The map used here follows the common procedure of illustrating the southern Federalist Electors along the coast. In North Carolina, Adams won the Fayetteville District, which is inland. The Elector from that district was re-elected in 1800 and cast a second vote for Adams. Chronicler3 13:40, 8 February 2006 (UTC) Chronicler3
Also, this NC Elector voted for Adams and Thomas Pinckney. It was the Jefferson Electors that scattered many of their votes among Federalist candidates for Vice President. Source: The North Carolina Electoral Vote: The People and the Process Behind the Vote (Raleigh: N.C. Secretary of State, 1988). Chronicler3 13:42, 8 February 2006 (UTC) Chronicler3
I don't believe that the map, which was pulled from the National Atlas, treats the split of colors within a state as geographically significant; rather, it is just supposed to be proportional in area to the split of votes.
Thank you very much for the (cited!) information about the NC elector. I incorporated it into the derivation (see next topic) and it's now in the main article. This leaves Wikipedia with only 15 tickets to figure out.
— DLJessup (talk) 04:15, 10 February 2006 (UTC)
[edit] Derivation of the ticket pairings
Just to demonstrate how the ticket pairings were found:
According to the National Archives, here's the state-by-state electoral vote in 1796:
| Name of candidate | CT | DE | GA | KY | MD | MA | NH | NJ | NY | NC | PA | RI | SC | TN | VT | VA | Total |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| John Adams, of Massachusetts | 9 | 3 | - | - | 7 | 16 | 6 | 7 | 12 | 1 | 1 | 4 | - | - | 4 | 1 | 71 |
| Thomas Jefferson, of Virginia | - | - | 4 | 4 | 4 | - | - | - | - | 11 | 14 | - | 8 | 3 | - | 20 | 68 |
| Thomas Pinckney, of South Carolina | 4 | 3 | - | - | 4 | 13 | - | 7 | 12 | 1 | 2 | - | 8 | - | 4 | 1 | 59 |
| Aaron Burr, of New York | - | - | - | 4 | 3 | - | - | - | - | 6 | 13 | - | - | 3 | - | 1 | 30 |
| Samuel Adams, of Massachusetts | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | 15 | 15 |
| O. Ellsworth, of Connecticut | - | - | - | - | - | 1 | 6 | - | - | - | - | 4 | - | - | - | - | 11 |
| George Clinton, of New York | - | - | 4 | - | - | - | - | - | - | - | - | - | - | - | - | 3 | 7 |
| John Jay, of New York | 5 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | 5 |
| James Iredell, of North Carolina | - | - | - | - | - | - | - | - | - | 3 | - | - | - | - | - | - | 3 |
| John Henry, of Maryland | - | - | - | - | 2 | - | - | - | - | - | - | - | - | - | - | - | 2 |
| S. Johnston, of North Carolina | - | - | - | - | - | 2 | - | - | - | - | - | - | - | - | - | - | 2 |
| George Washington, of Virginia | - | - | - | - | - | - | - | - | - | 1 | - | - | - | - | - | 1 | 2 |
| C. C. Pinckney, of South Carolina | - | - | - | - | - | - | - | - | - | 1 | - | - | - | - | - | - | 1 |
| Total electors | 9 | 3 | 4 | 4 | 10 | 16 | 6 | 7 | 12 | 12 | 15 | 4 | 8 | 3 | 4 | 21 | 138 |
Now, if we look at Connecticut, we find that there are 9 electors and 9 votes for John Adams. This means that each elector voted for Adams and one of the other candidates; in this case, there were 4 Adams/Pinckney tickets and 5 Adams/Clinton tickets. This simple analysis can be applied to all of the states except MD, NC, PA, and VA. Breaking up all of the other states by ticket, we get:
| Name of candidate | MD | NC | PA | VA | Other States | Total | ||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| John Adams, of Massachusetts | 7 | 1 | 1 | 1 | 43 | 11 | - | - | 5 | - | 2 | 71 |
| Thomas Jefferson, of Virginia | 4 | 11 | 14 | 20 | - | - | 8 | 7 | - | 4 | - | 68 |
| Thomas Pinckney, of South Carolina | 4 | 1 | 2 | 1 | 43 | - | 8 | - | - | - | - | 59 |
| Aaron Burr, of New York | 3 | 6 | 13 | 1 | - | - | - | 7 | - | - | - | 30 |
| Samuel Adams, of Massachusetts | - | - | - | 15 | - | - | - | - | - | - | - | 15 |
| O. Ellsworth, of Connecticut | - | - | - | - | - | 11 | - | - | - | - | - | 11 |
| George Clinton, of New York | - | - | - | 3 | - | - | - | - | - | 4 | - | 7 |
| John Jay, of New York | - | - | - | - | - | - | - | - | 5 | - | - | 5 |
| James Iredell, of North Carolina | - | 3 | - | - | - | - | - | - | - | - | - | 3 |
| John Henry, of Maryland | 2 | - | - | - | - | - | - | - | - | - | - | 2 |
| S. Johnston, of North Carolina | - | - | - | - | - | - | - | - | - | - | 2 | 2 |
| George Washington, of Virginia | - | 1 | - | 1 | - | - | - | - | - | - | - | 2 |
| C. C. Pinckney, of South Carolina | - | 1 | - | - | - | - | - | - | - | - | - | 1 |
| Total electors | 10 | 12 | 15 | 21 | 43 | 11 | 8 | 7 | 5 | 4 | 2 | 138 |
Now then, in Pennsylvania, there are only 15 electors, but Jefferson received 14 votes and Burr received 13, for a total of 27 votes. If we give 15 of these 27 votes to each elector, that leaves 12 votes which must be the second vote of the elector. In other words, we know that 12 electors in Pennsylvania voted for a Jefferson/Burr ticket. A similar analysis allows us to find some additional tickets in MD, NC, PA, and VA:
| Name of candidate | MD | NC | PA | VA | Other States | Total | |||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| John Adams, of Massachusetts | 5 | 1 | 1 | 1 | 44 | - | - | 11 | - | 5 | - | 2 | - | 1 | 71 |
| Thomas Jefferson, of Virginia | 3 | 4 | 1 | 4 | - | 24 | 14 | - | 9 | - | 6 | - | 2 | 1 | 68 |
| Thomas Pinckney, of South Carolina | 3 | 1 | 1 | 1 | 44 | - | - | - | 9 | - | - | - | - | - | 59 |
| Aaron Burr, of New York | 3 | 1 | 1 | 1 | - | 24 | - | - | - | - | - | - | - | - | 30 |
| Samuel Adams, of Massachusetts | - | - | - | 1 | - | - | 14 | - | - | - | - | - | - | - | 15 |
| O. Ellsworth, of Connecticut | - | - | - | - | - | - | - | 11 | - | - | - | - | - | - | 11 |
| George Clinton, of New York | - | - | - | 1 | - | - | - | - | - | - | 6 | - | - | - | 7 |
| John Jay, of New York | - | - | - | - | - | - | - | - | - | 5 | - | - | - | - | 5 |
| James Iredell, of North Carolina | - | 1 | - | - | - | - | - | - | - | - | - | - | 2 | - | 3 |
| John Henry, of Maryland | 2 | - | - | - | - | - | - | - | - | - | - | - | - | - | 2 |
| S. Johnston, of North Carolina | - | - | - | - | - | - | - | - | - | - | - | 2 | - | - | 2 |
| George Washington, of Virginia | - | 1 | - | 1 | - | - | - | - | - | - | - | - | - | - | 2 |
| C. C. Pinckney, of South Carolina | - | 1 | - | - | - | - | - | - | - | - | - | - | - | - | 1 |
| Total electors | 8 | 5 | 2 | 5 | 44 | 24 | 14 | 11 | 9 | 5 | 6 | 2 | 2 | 1 | 138 |
Now, Chronicler3 told us above that there was an Adams/Pinckney elector in North Carolina, citing (1988) The North Carolina Electoral Vote: The People and the Process Behind the Vote. Raleigh, North Carolina: North Carolina Secretary of State.. This leaves 4 electors in North Carolina and 4 votes for Jefferson, so we can derive all of the North Carolina tickets:
| Name of candidate | MD | PA | VA | Other States | Total | |||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| John Adams, of Massachusetts | 5 | 1 | 1 | 45 | - | - | 11 | - | 5 | - | 2 | - | 1 | - | - | 71 |
| Thomas Jefferson, of Virginia | 3 | 1 | 4 | - | 25 | 14 | - | 9 | - | 6 | - | 3 | 1 | 1 | 1 | 68 |
| Thomas Pinckney, of South Carolina | 3 | 1 | 1 | 45 | - | - | - | 9 | - | - | - | - | - | - | - | 59 |
| Aaron Burr, of New York | 3 | 1 | 1 | - | 25 | - | - | - | - | - | - | - | - | - | - | 30 |
| Samuel Adams, of Massachusetts | - | - | 1 | - | - | 14 | - | - | - | - | - | - | - | - | - | 15 |
| O. Ellsworth, of Connecticut | - | - | - | - | - | - | 11 | - | - | - | - | - | - | - | - | 11 |
| George Clinton, of New York | - | - | 1 | - | - | - | - | - | - | 6 | - | - | - | - | - | 7 |
| John Jay, of New York | - | - | - | - | - | - | - | - | 5 | - | - | - | - | - | - | 5 |
| James Iredell, of North Carolina | - | - | - | - | - | - | - | - | - | - | - | 3 | - | - | - | 3 |
| John Henry, of Maryland | 2 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | 2 |
| S. Johnston, of North Carolina | - | - | - | - | - | - | - | - | - | - | 2 | - | - | - | - | 2 |
| George Washington, of Virginia | - | - | 1 | - | - | - | - | - | - | - | - | - | - | 1 | - | 2 |
| C. C. Pinckney, of South Carolina | - | - | - | - | - | - | - | - | - | - | - | - | - | - | 1 | 1 |
| Total electors | 8 | 2 | 5 | 45 | 25 | 14 | 11 | 9 | 5 | 6 | 2 | 2 | 1 | 1 | 1 | 138 |
You can almost see now where the minimum and maximum counts come from: for any ticket, you take the number of electors in that ticket's column under “Other states” as a minimum (or 0 if there is no column), and you add the smaller of the ticket's members in each of the MD, PA, and VA columns to get the maximum. There's just one catch: in Virginia, there are 4 votes for Jefferson and 1 vote for Washington, or 5 votes for Virginians. Constitutionally, no Virginia elector was allowed to vote for two Virginians. Thus, each Virginia elector voted for one Virginian and one non-Virginian. Hence, you can only add in the Virginia column if one member of the ticket is a Virginian and one a non-Virginian.
— DLJessup (talk) 04:07, 10 February 2006 (UTC)
[edit] Why didn't GW run again?
Did GW's urge to retire override the requests to stay in, or what? Given that he was basically unanimous the first two times, it's probably safe to assume that he would have been elected again if he'd run again.
Since it looks like the parties were basically manipulating the vote, I've modified the text to say so explicitly. If this is incorrect or misleading, then slap my hand and change it back... --Scott McNay 05:21, 23 August 2006 (UTC)
It because he was selfish and did not want any one else to have a chance peolpe voted for him twice I think thats the reason he lost the third time because he got big headed during his second term —Preceding unsigned comment added by 70.167.90.229 (talk) 01:04, 30 November 2007 (UTC)
[edit] Possible Correction
In the article, it states that Adams/Jefferson were the only President and Vice-President from different parties. However, Andrew Johnson was a Democrat and Abraham Lincoln a Republican. Although they ran under a different name, I believe they called themselves the Union party, no such party actually existed and history books today list Lincoln as a Republican and Johnson as a Democrat. I hesitate to change the actual page (I could spend my life editing these pages) but perhaps I will do so later if no one else does.
24.159.34.49 03:48, 16 August 2007 (UTC) dzannucci
[edit] the myth of only two parties
It would be nice if the graphic reflected the table, rather than showing that the votes for Adams and Jefferson add up to the "total". —Tamfang 08:14, 15 October 2007 (UTC)

