Sherman Township, Antelope County, Nebraska
From Wikipedia, the free encyclopedia
| Sherman Township | |
| Location in Antelope County | |
| Coordinates: | |
|---|---|
| Country | United States |
| State | Nebraska |
| County | Antelope |
| Area | |
| - Total | 35.74 sq mi (92.56 km²) |
| - Land | 35.71 sq mi (92.48 km²) |
| - Water | 0.03 sq mi (0.08 km²) 0.09% |
| Elevation | 1,755 ft (535 m) |
| Population (2000) | |
| - Total | 98 |
| - Density | 2.7/sq mi (1.1/km²) |
| GNIS feature ID | 0838246 |
Sherman Township is one of twenty-four townships in Antelope County, Nebraska, United States. The population was 98 at the 2000 census. A 2006 estimate placed the township's population at 94.[1]
[edit] See also
[edit] References
- ^ Subcounty population estimates: Nebraska 2000-2006 (CSV). United States Census Bureau, Population Division (2007-06-28). Retrieved on 2008-02-23.
[edit] External links
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