User:Rainmonger/Physics equations

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[edit] Kinematics

Many kinematics problems are given to students in high school and college physics courses which involve the five following measurable quantities of a body in motion:

  • a\, - acceleration (most often assumed to be constant)
  • t\, - time elapsed
  • v_f\, - final velocity (this variable may also be represented by just v\,)
  • v_i\, - initial velocity (this variable may also be represented by u\,)
  • x\, - distance traveled (this variable may also be represented by d\, or s\,)

If one knows any three of the above quantities for a given situation, then one may solve for any of the other two. The equations below demonstrate this property.

[edit] Solving for (constant) acceleration

[edit] Time is unknown

a=\dfrac{v_f^2-v_i^2}{2x}\,

[edit] Final velocity is unknown

a=2\dfrac{x-v_it}{t^2}\,

[edit] Initial velocity is unknown

a=2\dfrac{v_ft-x}{t^2}\,

[edit] Distance is unknown

a=\dfrac{v_f-v_i}{t}\,

[edit] Solving for time

[edit] Acceleration is unknown (but constant)

t=\dfrac{2x}{v_f+v_i}\,

[edit] Final velocity is unknown

t=\dfrac{-v_i+\sqrt{v_i^2+2ax}}{a}\,

[edit] Initial velocity is unknown

t=\dfrac{v_f+\sqrt{v_f^2+2ax}}{a}\,

[edit] Distance is unknown

t=\dfrac{v_f-v_i}{a}\,

[edit] Solving for final velocity

[edit] Acceleration is unknown (but constant)

v_f=\dfrac{2x}{t}-v_i\,

[edit] Time is unknown

v_f=\sqrt{v_i^2+2ax}\,

[edit] Initial velocity is unknown

v_f=\dfrac{2x+at^2}{2t}\,

[edit] Distance is unknown

v_f=v_i+at\,

[edit] Solving for initial velocity

[edit] Acceleration is unknown (but constant)

v_i=\dfrac{2x}{t}-v_f\,

[edit] Time is unknown

v_i=\sqrt{v_f^2-2ax}\,

[edit] Final velocity is unknown

v_i=\dfrac{2x-at^2}{2t}\,

[edit] Distance is unknown

v_i=v_f-at\,

[edit] Solving for distance

[edit] Acceleration is unknown (but constant)

x=\dfrac{v_f+v_i}{2}t\,

[edit] Time is unknown

x=\dfrac{v_f^2-v_i^2}{2a}\,

[edit] Final velocity is unknown

x=v_it+\tfrac{1}{2}at^2\,

[edit] Initial velocity is unknown

x=v_ft-\tfrac{1}{2}at^2\,