User:Mr splosh

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hello world!

  • Team B faced 47.2 overs, so their runrate is \frac{267}{47\tfrac{2}{6}} \approx 5.64
  • Assuming that Team A and Team B had previously played as in the game in scenario one, the new net run rate for team A would be \frac{287+265}{50+ 50}-\frac{243+267}{50+47.33} = \frac{552}{100}-\frac{510}{97.33} \approx 0.28

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  • Team B faced 47.2 overs, so their runrate is \frac{267}{47\tfrac{1}{3}} = \frac{267}{\tfrac{142}{3}} = \frac{801}{142} \approx 5.64
  • Assuming that Team A and Team B had previously played as in the game in scenario one, the new net run rate for team A would be \frac{287+265}{50+ 50}-\frac{243+267}{50+47\tfrac{1}{3}} = \frac{552}{100}-\frac{510}{97\tfrac{1}{3}} \approx 0.28

[edit] check the table

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