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$F_c = \frac{mv^2}{r}$

$A_c = \frac{v^2}{r}$

$G_F = \frac{G \times M_1 \times M_2}{r^2}$

$G_a = \frac{G \times M_1}{r^2}$

$W o r k = Δ K E + Δ U g + Δ W f$

$F \times \Delta x \times \cos \theta = \frac{1}{2}mv^2 + mg \Delta h + \mu F_n \cos \theta \Delta x$

$\Delta KE = \frac{1}{2} mv^2$

$Δ U g = m g Δ h$

$W f = μ m g sinθ$

$U 0 + K E 0 = U 1 + K E 1 + W f$

$U_G = - \frac {GM_em}{r}$

$P = \frac {W}{t}$

$Work = Joules = Nm = \frac {kgm^2}{s^2}$

$Power = Watts = \frac {Nm}{s} = \frac {kgm^2}{s^3}$

$sin 2 x + cos 2 x = 1$

$f(x) = f(a) \times f(b) \Longrightarrow f'(x) = [f'(a) \times f(b)] + [f'(a) \times f(b)]$

$f'(x) = [f'(a) \times f(b)] + [f'(b) \times f(a)]$

$1 h p = 745.70 W a t t s$

$a_1 = a_0 - \frac {f(a_0)}{f'(a_0)}$

Work = Change in Kinetic Energy + Change in Potential Energy + Work of Friction

F(displacement)(change in inclination) = (1/2mv^2) + (mg)(change in height) + (mu)(Force Normal)(cosine theta)(displacement)

Change in Kinetic Energy = (1/2)mv^2

Change in Potential Energy = mg(change in height)

Work of Friction = (mu)(mg)(sin theta)

PE(0) + KE(0) = PE(1) + KE(1) + W(f)

Absolute Gravitational Potential Energy = F(G) = -(GM(e)m(2))/r

Power = Work / Time