Hobart Township, Lake County, Indiana
From Wikipedia, the free encyclopedia
| Hobart Township | |
| Coordinates: | |
|---|---|
| Country | United States |
| State | Indiana |
| County | Lake |
| Area | |
| - Total | 26.05 sq mi (67.46 km²) |
| - Land | 25.38 sq mi (65.74 km²) |
| - Water | 0.66 sq mi (1.71 km²) |
| Elevation [1] | 627 ft (191 m) |
| Population (2000) | |
| - Total | 39,636 |
| - Density | 1,561.46/sq mi (602.88/km²) |
| FIPS code | 18-34132[2] |
| GNIS feature ID | 453414 |
Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2000 census, its population was 39,636.
[edit] References
- ^ US Board on Geographic Names. United States Geological Survey (2007-10-25). Retrieved on 2008-01-31.
- ^ American FactFinder. United States Census Bureau. Retrieved on 2008-01-31.
[edit] External links
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