Birch–Murnaghan equation of state

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In continuum mechanics, an equation of state suitable for modeling solids is naturally rather different from the ideal gas law. A solid has a certain equilibrium volume V0, and the energy increases quadratically as volume is increased or decreased a small amount from that value. The simplest plausible dependence of energy on volume would be a harmonic solid, with


E = E_0 + \frac{1}{2} B_0 \frac{(V-V_0)^2}{V_0}.

The next simplest reasonable model would be with a constant bulk modulus


B = - V \left( \frac{\partial P}{\partial V} \right)_T.	(2)

E = E_0 + B_0 \left( V_0 - V + V \ln(V/V_0) \right).

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[edit] Murnaghan equation of state

A more sophisticated equation of state was derived by Francis D. Murnaghan of Johns Hopkins University in 1944[1]. To begin with, we consider the pressure

  P = - \left( \frac{\partial E}{\partial V} \right)_S	(1)

and the bulk modulus


B = - V \left( \frac{\partial P}{\partial V} \right)_T.	(2)

Experimentally, the bulk modulus pressure derivative


B' =  \left( \frac{\partial B}{\partial P} \right)_T	(3)

is found to change little with pressure. If we take B' = B'0 to be a constant, then

B = B0 + B'0P(4)

where B0 is the value of B when P = 0. We may equate this with (2) and rearrange as


\frac{d V}{V} = -\frac{d P}{B_0 + B'_0 P}.	(5)

Integrating this results in


P(V) = \frac{B_0}{B'_0} \left(\left(\frac{V_0}{V}\right)^{B'_0}
    - 1\right)	(6)

or equivalently


V(P) = V_0 \left(1+B'_0
    \frac{P}{B_0}\right)^{-1/B'_0}.		(7)

Substituting (6) into E = E_0 - \int P
dV then results in the equation of state for energy.


E(V) = E_0
 + \frac{ B_0 V }{ B_0' } \left( \frac{ (V_0/V)^{B_0'} }{ B_0' - 1 } + 1 \right)
 - \frac{ B_0 V_0 }{ B_0' - 1 }. 	(8)

Many substances have a fairly constant B'0 of about 3.5.

[edit] Birch–Murnaghan equation of state

The third-order Birch–Murnaghan isothermal equation of state, published in 1947 by Francis Birch of Harvard[2], is given by:


P(V)=\frac{3B_0}{2}
\left[\left(\frac{V_0}{V}\right)^\frac{7}{3} - 
\left(\frac{V_0}{V}\right)^\frac{5}{3}\right]
\left\{1+\frac{3}{4}\left(B_0^\prime-4\right)
\left[\left(\frac{V_0}{V}\right)^\frac{2}{3} - 1\right]\right\}

Again, E(V) is found by integration of the pressure:


E(V) = E_0 + \frac{9V_0B_0}{16}
\left\{
\left[\left(\frac{V_0}{V}\right)^\frac{2}{3}-1\right]^3B_0^\prime + 
\left[\left(\frac{V_0}{V}\right)^\frac{2}{3}-1\right]^2
\left[6-4\left(\frac{V_0}{V}\right)^\frac{2}{3}\right]\right\}

[edit] See also

[edit] References

  • ^  F.D. Murnaghan, 'The Compressibility of Media under Extreme Pressures', in Proceedings of the National Academy of Sciences, vol. 30, pp. 244-247, 1944. [3]
  • ^  Francis Birch, 'Finite Elastic Strain of Cubic Crystals', in Physical Review, vol. 71, pp. 809-824 (1947). [4]

[edit] External links

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