1948 NBA Playoffs
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The 1948 NBA Playoffs was the postseason tournament of the National Basketball Association's 1947-1948 season. The tournament concluded with the Western Conference champion Baltimore Bullets defeating the Eastern Conference champion Philadelphia Warriors, four games to two in the NBA Finals.
(Prior to 1950, the NBA was called the Basketball Association of America (BAA))
Contents |
[edit] Western Division Tiebreaker Games
- March 23: Washington 70 at Chicago 74
- March 25: Baltimore 75 at Washington 72
[edit] Quarterfinals
Baltimore Bullets vs. New York Knicks: Bullets win series 2-1
Chicago Stags vs. Boston Celtics: Stags win series 2-1
[edit] Semifinals
Philadelphia Warriors vs. St. Louis Bombers: Warriors win series 4-3
Baltimore Bullets vs. Chicago Stags: Bullets win series 2-0
[edit] NBA Finals
Baltimore Bullets vs. Philadelphia Warriors: Bullets win series 4-2
[edit] Bracket
See also: 1948 NBA Finals
| Quarterfinals | Semifinals | NBA Finals | |||||||||||
| W2 | Baltimore | 2 | |||||||||||
| E2 | New York | 1 | |||||||||||
| W3 | Chicago | 0 | |||||||||||
| W2 | Baltimore | 2 | |||||||||||
| E3 | Boston | 1 | |||||||||||
| W3 | Chicago | 2 | |||||||||||
| W2 | Baltimore | 4 | |||||||||||
| E1 | Philadelphia | 2 | |||||||||||
| W1 | St. Louis | 3 | |||||||||||
| E1 | Philadelphia | 4 | |||||||||||
